Level 4 · Mathematics M4.2

Percentages, proportion and growth

Use percentages to find changes, and see how amounts grow or shrink over time.

Increase and decrease an amount with a multiplier, find a percentage change, and work back to the original amount. Compare simple and compound interest, model growth and decay, combine ratios, and write and graph direct and inverse proportion.

You are ready for this book if

You can find 15% of 80 without a calculator.

Written and drawn by attnom. Free to read, print and share.

M4.2.1 Chapter 1

Percentage increase and decrease

How do I add 12% to 250 in one step?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

A packet holds 250 seeds. A new packet holds 12% more. How many seeds is that?

Percent means out of 100. So 12% is 12/100, which is 0.12. 12% of 250 is 0.12 × 250 = 30. Add that to the start: 250 + 30 = 280.

That took two steps. There is a way to do it in one.

Draw it first

Add the rise to the start

  1. A bar labelled Start: 250 seeds, with the label 100%. A second bar labelled After the rise: 280 seeds, with the label 112%, is longer by a dotted piece. A box 250 joins to a box 280 by an arrow labelled × 1.12.Start: 250 seeds100%

    1 The start is 100% of the seeds. That bar is 250 seeds.

  2. A bar labelled Start: 250 seeds, with the label 100%. A second bar labelled After the rise: 280 seeds, with the label 112%, is longer by a dotted piece. A box 250 joins to a box 280 by an arrow labelled × 1.12.Start: 250 seeds100%After the rise: 280 seeds112%

    2 The rise adds 12% more. The new bar is 112% of the start, and the extra piece is dotted.

  3. A bar labelled Start: 250 seeds, with the label 100%. A second bar labelled After the rise: 280 seeds, with the label 112%, is longer by a dotted piece. A box 250 joins to a box 280 by an arrow labelled × 1.12.Start: 250 seeds100%After the rise: 280 seeds112%250× 1.12280

    3 112% is 1.12 as a decimal. One multiplication takes 250 to 280.

The start is 100%. A rise of 12% makes 100% + 12% = 112%. As a decimal, 112% is 1.12. The number 1.12 is the multiplier. Multiply by it, and the rise is done.

Worked example

Increase 250 by 12% using a multiplier.

  1. A rise of 12% makes 100% + 12% = 112% of the start.
  2. 112% as a decimal is 1.12. This is the multiplier.
  3. Multiply the start by the multiplier: 250 × 1.12 = 280.

Answer: 250 × 1.12 = 280

A fall works the same way. A fall of 35% leaves 100% − 35% = 65% of the start. As a decimal that is 0.65. The multiplier for a fall is below 1.

A bar labelled Start: 240 seeds, with the label 100%. A shorter bar labelled After the fall: 156 seeds, with the label 65%. The 35% that is missing is a dashed outline.Start: 240 seeds100%After the fall: 156 seeds65%
A fall of 35% leaves 65% of the start. The missing 35% is the dashed part.

Worked example

Decrease 240 by 35%.

  1. A fall of 35% leaves 100% − 35% = 65% of the start.
  2. 65% as a decimal is 0.65. This is the multiplier.
  3. Multiply: 240 × 0.65 = 156.

Answer: 240 × 0.65 = 156

A table with the head Change and Multiplier. Rows: Rise of 5%, 1.05; Rise of 12%, 1.12; Fall of 15%, 0.85; Fall of 40%, 0.6.ChangeMultiplierRise of 5%1.05Rise of 12%1.12Fall of 15%0.85Fall of 40%0.6
A rise adds to 1. A fall takes away from 1.

Sometimes you are given the old and the new amount and asked how much it changed. A percentage change says the change as a percent of the amount you started with.

Work out the change: new minus original. Divide it by the original. Multiply by 100. As a formula: percentage change = (new − original) ÷ original × 100.

A bar labelled Original: 80 seeds, with the label 100%. A longer bar labelled New: 92 seeds, with the label 115%. The extra dotted piece is 12 seeds.Original: 80 seeds100%New: 92 seeds115%
The dotted piece is the change, 12 seeds. It is measured against the original, which is 100%.

Worked example

Find the percentage change from 80 to 92.

  1. The change is new minus original: 92 − 80 = 12.
  2. Divide the change by the original: 12 ÷ 80 = 0.15.
  3. Multiply by 100: 0.15 × 100 = 15.
  4. The amount rose by 15%.

Answer: A rise of 15%

See it three ways

With things

Take 80 stones. Put them in 10 piles of 8. Add 12 more stones. That is one more pile and half a pile.

As a picture

A bar labelled 80 stones in 10 piles of 8, with the label 100%, cut into 10 equal parts. A second bar labelled 12 stones added, with the label 15%, covers one and a half of the parts.80 stones in 10 piles of 8100%12 stones added15%

In symbols

12 ÷ 80 × 100 = 15%.

Try it

Cut a strip

You need: paper, a ruler, a pencil.

  1. Draw a strip 10 cm long. Let the whole strip stand for 100%. Mark every 1 cm.
  2. Shade the first 6.5 cm from the left. Leave the last 3.5 cm white.

What you will see: The shaded part is 65% of the strip. A fall of 35% leaves 65%, so the multiplier is 0.65.

If you cannot try it, this is what happens.
A bar labelled Whole strip: 10 cm, with the label 100%, cut into 10 equal parts. A second bar labelled Shaded: 6.5 cm, with the label 65%, is hatched and covers six and a half of the parts.Whole strip: 10 cm100%Shaded: 6.5 cm65%

A wrong idea many people have

To increase 250 by 12%, add 12: 250 + 12 = 262.

Why it feels right: The words say "12" and "add", so it feels natural to add the 12 you can see.

The test that breaks it: Work out 12% of 250. It is 0.12 × 250 = 30, not 12. The rise is 30 seeds, so 262 is too low.

What is true: The percent is a fraction of the start, not a number to add. Use the multiplier: 250 × 1.12 = 280.

A wrong idea many people have

The amount falls from 125 to 100, so the fall is 25 out of 100, which is 25%.

Why it feels right: The new amount is the one you are looking at, and 100 makes the sum look like a percent already.

The test that breaks it: A fall of 25% would leave 125 × 0.75 = 93.75, not 100. Check by multiplying.

What is true: Divide by the original amount, 125. The change 25 ÷ 125 = 0.2, so the fall is 20%.

Key words

percent
out of 100. So 12% is 12 out of 100, or 0.12.
multiplier
the number you multiply by to change an amount, such as 1.12 for a rise of 12%.
percentage change
the change divided by the original amount, times 100.

Back to your guess

The answer is B: Multiply 250 by 1.12 to get 280.

12% of 250 is 30, and that is what 0.12 gives. The rise adds 30 to the 250, so the new amount is 280. Multiplying by 1.12 does both steps at once.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. Which multiplier increases an amount by 8%?

    Tap your answer.
    1. Not this one. This is 8% of the amount, not the amount plus 8%. A rise keeps the whole 100% and adds 8% to it, so 1 + 0.08. Go to M4.2.1. Try another.

    2. Not this one. Read the decimal carefully. 1.8 is 1 + 0.8, which is a rise of 80%. A rise of 8% is 1 + 0.08. Go to M4.2.1. Try another.

    3. Yes, that is right. A rise of 8% makes 100% + 8% = 108% of the start, which is 1.08 as a decimal.

    4. Not this one. This is the multiplier for a fall of 8%. A rise adds to 1. Go to M4.2.1. Try another.

    See the answer

    1.08

    A rise of 8% makes 100% + 8% = 108% of the start, which is 1.08 as a decimal.

    • If you chose A: This is 8% of the amount, not the amount plus 8%. A rise keeps the whole 100% and adds 8% to it, so 1 + 0.08. Go to M4.2.1.
    • If you chose B: Read the decimal carefully. 1.8 is 1 + 0.8, which is a rise of 80%. A rise of 8% is 1 + 0.08. Go to M4.2.1.
    • If you chose D: This is the multiplier for a fall of 8%. A rise adds to 1. Go to M4.2.1.
  2. The picture shows 360 being increased by 25%. What number goes in the empty box?

    A box 360 joins to an empty box ? by an arrow labelled × 1.25.360× 1.25?
    Tap your answer.
    1. Yes, that is right. 360 × 1.25 = 450. The 25% rise is 90, and 360 + 90 = 450.

    2. Not this one. You added 25 to 360. A rise of 25% is a quarter of 360 added on, which is 90. Go to M4.2.1. Try another.

    3. Not this one. This is 25% of 360, the size of the rise. The question asks for the new amount, which is 360 plus 90. Go to M4.2.1. Try another.

    4. Not this one. This is 360 decreased by 25%. The arrow says × 1.25, which is bigger than 1, so the amount grows. Go to M4.2.1. Try another.

    See the answer

    450

    360 × 1.25 = 450. The 25% rise is 90, and 360 + 90 = 450.

    • If you chose B: You added 25 to 360. A rise of 25% is a quarter of 360 added on, which is 90. Go to M4.2.1.
    • If you chose C: This is 25% of 360, the size of the rise. The question asks for the new amount, which is 360 plus 90. Go to M4.2.1.
    • If you chose D: This is 360 decreased by 25%. The arrow says × 1.25, which is bigger than 1, so the amount grows. Go to M4.2.1.
  3. Decrease 200 by 35%. The picture shows the bars.

    A bar labelled Start: 200, with the label 100%. A shorter bar labelled After the fall, with the label 65%. The missing 35% is a dashed outline.Start: 200100%After the fall65%
    Tap your answer.
    1. Not this one. You took 35 away from 200. A fall of 35% takes away 35 out of every 100, which is 70 from 200. Go to M4.2.1. Try another.

    2. Not this one. This is 35% of 200, the size of the fall. The question asks for what is left: 200 minus 70. Go to M4.2.1. Try another.

    3. Not this one. This adds 35% instead of taking it away. A fall uses a multiplier below 1. Go to M4.2.1. Try another.

    4. Yes, that is right. A fall of 35% leaves 65%, so the multiplier is 0.65. 200 × 0.65 = 130.

    See the answer

    130

    A fall of 35% leaves 65%, so the multiplier is 0.65. 200 × 0.65 = 130.

    • If you chose A: You took 35 away from 200. A fall of 35% takes away 35 out of every 100, which is 70 from 200. Go to M4.2.1.
    • If you chose B: This is 35% of 200, the size of the fall. The question asks for what is left: 200 minus 70. Go to M4.2.1.
    • If you chose C: This adds 35% instead of taking it away. A fall uses a multiplier below 1. Go to M4.2.1.
  4. What is the percentage change from 50 to 56?

    Tap your answer.
    1. Not this one. The change is 6, but 6 is not yet a percent. Divide 6 by the original, 50, and multiply by 100. Go to M4.2.1. Try another.

    2. Yes, that is right. The change is 56 − 50 = 6. Then 6 ÷ 50 × 100 = 12.

    3. Not this one. You divided the change by the new amount, 56. A percentage change is measured against the original, 50. Go to M4.2.1. Try another.

    4. Not this one. The new amount is 112% of the original, but that is the whole amount. The change is only the 12% above the 100%. Go to M4.2.1. Try another.

    See the answer

    12%

    The change is 56 − 50 = 6. Then 6 ÷ 50 × 100 = 12.

    • If you chose A: The change is 6, but 6 is not yet a percent. Divide 6 by the original, 50, and multiply by 100. Go to M4.2.1.
    • If you chose C: You divided the change by the new amount, 56. A percentage change is measured against the original, 50. Go to M4.2.1.
    • If you chose D: The new amount is 112% of the original, but that is the whole amount. The change is only the 12% above the 100%. Go to M4.2.1.
  5. An amount goes from 160 down to 120. What is the percentage change?

    Tap your answer.
    1. Not this one. You divided the change, 40, by the new amount, 120. Divide by the original amount, 160. Go to M4.2.1. Try another.

    2. Not this one. 120 is 75% of 160, so 75% is what is left. The fall is the other 25%. Go to M4.2.1. Try another.

    3. Not this one. The new amount is smaller than the original, so the amount fell. A rise needs a bigger new amount. Go to M4.2.1. Try another.

    4. Yes, that is right. The change is 160 − 120 = 40. Then 40 ÷ 160 × 100 = 25. The amount fell.

    See the answer

    A fall of 25%

    The change is 160 − 120 = 40. Then 40 ÷ 160 × 100 = 25. The amount fell.

    • If you chose A: You divided the change, 40, by the new amount, 120. Divide by the original amount, 160. Go to M4.2.1.
    • If you chose B: 120 is 75% of 160, so 75% is what is left. The fall is the other 25%. Go to M4.2.1.
    • If you chose C: The new amount is smaller than the original, so the amount fell. A rise needs a bigger new amount. Go to M4.2.1.
  6. Increase 160 by 15%.

    See the answer

    184

    A rise of 15% makes 115% of the start, so the multiplier is 1.15. 160 × 1.15 = 184.

  7. A plant grows from 40 cm to 46 cm. What is the percentage increase? Type the number only.

    See the answer

    15

    The change is 46 − 40 = 6 cm. Then 6 ÷ 40 × 100 = 15. The plant grew by 15%.

Keep it

Copy this into your exercise book.

Rise: multiply by 1 + the rate. Fall: multiply by 1 − the rate. Percentage change = change ÷ original × 100. Always divide by the original.

Draw: A bar of 100% and a longer bar of 112%, with an arrow labelled × 1.12 between them.

M4.2.2 Chapter 2

Finding the original amount

A herd grew by 25% and now has 150 goats. How many goats did it have before?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

Last year a herd had some goats. It grew by 20% and now has 96 goats. We want the number it started with, the original amount.

The start is 100%. After a rise of 20%, the herd is 120% of the start. So 96 goats is 120% of the original amount.

Draw it first

Work back from the new amount

  1. A bar labelled New herd: 96 goats, with the label 120%. A shorter bar labelled Old herd: ? goats, with the label 100%. A box ? joins to a box 96 by an arrow labelled × 1.2, and a return arrow labelled ÷ 1.2 goes back.New herd: 96 goats120%

    1 The new herd is 96 goats. That is 120% of the original.

  2. A bar labelled New herd: 96 goats, with the label 120%. A shorter bar labelled Old herd: ? goats, with the label 100%. A box ? joins to a box 96 by an arrow labelled × 1.2, and a return arrow labelled ÷ 1.2 goes back.New herd: 96 goats120%Old herd: ? goats100%

    2 The old herd is the shorter bar. We do not know it yet.

  3. A bar labelled New herd: 96 goats, with the label 120%. A shorter bar labelled Old herd: ? goats, with the label 100%. A box ? joins to a box 96 by an arrow labelled × 1.2, and a return arrow labelled ÷ 1.2 goes back.New herd: 96 goats120%Old herd: ? goats100%?× 1.296÷ 1.2

    3 The rise multiplied the old herd by 1.2. To go back, divide the new herd by 1.2.

A rise multiplies by 1.2. Going back undoes the multiplying, so divide by 1.2. Divide by the multiplier, whether the change was a rise or a fall. To divide by 1.2, multiply both numbers by 10 first: 96 ÷ 1.2 = 960 ÷ 12 = 80.

Worked example

A herd grew by 20% and now has 96 goats. Find the original amount.

  1. The new amount is 100% + 20% = 120% of the original.
  2. 120% as a decimal is 1.2. So original × 1.2 = 96.
  3. Go back by dividing by the multiplier: 96 ÷ 1.2 = 80.
  4. Check: 80 × 1.2 = 96. So the herd had 80 goats before.

Answer: 96 ÷ 1.2 = 80

A bar labelled Old herd: 80 goats, with the label 100%. A longer bar labelled New herd: 96 goats, with the label 120%, whose extra dotted piece is 16 goats.Old herd: 80 goats100%New herd: 96 goats120%
The rise is 20% of the old herd: 16 goats. It is not 20% of the new herd.

A wrong idea many people have

To undo a rise of 20%, take 20% off 96.

Why it feels right: A rise and a fall of the same percent sound like opposites that cancel.

The test that breaks it: 20% of 96 is 19.2, and 96 − 19.2 = 76.8. Now check by rising 20%: 76.8 × 1.2 = 92.16, not 96.

What is true: The rise was 20% of the old amount, 80, and not 20% of 96. Divide by 1.2 to reach 80.

A fall works the same way. The multiplier is below 1, and you still divide by it.

A bar labelled Start: ? litres, with the label 100%. A shorter bar labelled Now: 140 litres, with the label 70%. The missing 30% is a dashed outline.Start: ? litres100%Now: 140 litres70%
140 litres is 70% of the start.

Worked example

A tank lost 30% of its water and now holds 140 litres. How much did it hold at the start?

  1. A fall of 30% leaves 100% − 30% = 70% of the start.
  2. 70% as a decimal is 0.7. So start × 0.7 = 140.
  3. Divide by the multiplier: 140 ÷ 0.7 = 200.
  4. The tank held 200 litres. Check: 200 × 0.7 = 140.

Answer: 140 ÷ 0.7 = 200

Now a puzzle. A herd of 200 goats grows by 10%. Then it falls by 10%. Is it back where it began?

A box 200 joins to a box 220 by an arrow labelled × 1.1. That box joins to a box 198 by an arrow labelled × 0.9.200× 1.1220× 0.9198
The herd ends at 198, which is 2 below where it began.

It is not back. The rise of 10% was worked out on 200. The fall of 10% was worked out on 220, which is a bigger amount. A bigger amount loses more.

Worked example

A herd of 200 goats grows by 10%, then falls by 10%. How does the end compare with the start?

  1. A rise of 10% has multiplier 1.1: 200 × 1.1 = 220.
  2. A fall of 10% has multiplier 0.9: 220 × 0.9 = 198.
  3. One multiplier does both: 1.1 × 0.9 = 0.99.
  4. The herd ends at 0.99 of the start, which is 1% less.

Answer: Less, by 1%

See it three ways

With things

Take 100 stones. Add 10%: that is 10 more, so 110 stones. Now take away 10% of the 110: that is 11 stones. 99 are left.

As a picture

A bar labelled Start: 100 stones, with the label 100%. A longer bar labelled After the rise: 110 stones, with the label 110%. A third bar labelled After the fall: 99 stones, with the label 99%, with a short dashed outline for the 1% missing.Start: 100 stones100%After the rise: 110 stones110%After the fall: 99 stones99%

In symbols

100 × 1.1 × 0.9 = 99.

Try it

Try any number

You need: paper, a pencil.

  1. Write any whole number you like. Here we use 300.
  2. Raise it by 10%. Write the answer.
  3. Lower that answer by 10%. Write the new answer.

What you will see: You end below where you began. With 300 you reach 297. Try other numbers: the end is always 0.99 of the start.

If you cannot try it, this is what happens.
A box 300 joins to a box 330 by an arrow labelled × 1.1. That box joins to a box 297 by an arrow labelled × 0.9.300× 1.1330× 0.9297

A wrong idea many people have

A rise of 10% and then a fall of 10% cancel, so you end where you began.

Why it feels right: Plus 10 and minus 10 do cancel. The same number appears twice, so it feels the same here.

The test that breaks it: Take 100. A rise of 10% gives 110. A fall of 10% takes off 10% of 110, which is 11. That leaves 99, not 100.

What is true: Each percent is of a different amount. Multiply the multipliers: 1.1 × 0.9 = 0.99.

Key words

original amount
the amount before the change. It is 100%.

Back to your guess

The answer is C: Divide 150 by 1.25 to get 120.

The 25% rise was worked out on the old herd, not on 150. The new herd is 125% of the old herd, so divide 150 by 1.25. That gives 120. Check: 120 × 1.25 = 150.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. After a 40% rise an amount is 210. What was the original amount?

    Tap your answer.
    1. Not this one. You took 40% off 210. The 40% rise was worked out on the original amount, which is smaller than 210, so divide by 1.4. Go to M4.2.2. Try another.

    2. Not this one. You took 40 away from 210. The rise is 40% of the original, not the number 40. Go to M4.2.2. Try another.

    3. Not this one. You multiplied by 1.4 again. That makes the amount bigger, but the original was smaller than 210. Go to M4.2.2. Try another.

    4. Yes, that is right. A rise of 40% is a multiplier of 1.4. Divide to go back: 210 ÷ 1.4 = 150.

    See the answer

    150

    A rise of 40% is a multiplier of 1.4. Divide to go back: 210 ÷ 1.4 = 150.

    • If you chose A: You took 40% off 210. The 40% rise was worked out on the original amount, which is smaller than 210, so divide by 1.4. Go to M4.2.2.
    • If you chose B: You took 40 away from 210. The rise is 40% of the original, not the number 40. Go to M4.2.2.
    • If you chose C: You multiplied by 1.4 again. That makes the amount bigger, but the original was smaller than 210. Go to M4.2.2.
  2. After a 20% fall an amount is 64. What was it before?

    Tap your answer.
    1. Not this one. You added 20% of 64. The fall was 20% of the original, which is more than 64, so divide by 0.8. Go to M4.2.2. Try another.

    2. Yes, that is right. A fall of 20% leaves 80%, a multiplier of 0.8. Divide to go back: 64 ÷ 0.8 = 80.

    3. Not this one. You added 20 to 64. The fall is 20% of the original, not the number 20. Go to M4.2.2. Try another.

    4. Not this one. You multiplied by 0.8 again, which is a second fall. The original was bigger than 64. Go to M4.2.2. Try another.

    See the answer

    80

    A fall of 20% leaves 80%, a multiplier of 0.8. Divide to go back: 64 ÷ 0.8 = 80.

    • If you chose A: You added 20% of 64. The fall was 20% of the original, which is more than 64, so divide by 0.8. Go to M4.2.2.
    • If you chose C: You added 20 to 64. The fall is 20% of the original, not the number 20. Go to M4.2.2.
    • If you chose D: You multiplied by 0.8 again, which is a second fall. The original was bigger than 64. Go to M4.2.2.
  3. After a 25% fall an amount is 90. What was it before?

    Tap your answer.
    1. Not this one. You added 25% of 90. The fall was 25% of the original, which is more than 90, so divide by 0.75. Go to M4.2.2. Try another.

    2. Not this one. You added 25 to 90. The fall is 25% of the original, not the number 25. Go to M4.2.2. Try another.

    3. Yes, that is right. A fall of 25% leaves 75%, a multiplier of 0.75. 90 ÷ 0.75 = 120.

    4. Not this one. You took 25% off 90, which is a second fall. The original was bigger than 90. Go to M4.2.2. Try another.

    See the answer

    120

    A fall of 25% leaves 75%, a multiplier of 0.75. 90 ÷ 0.75 = 120.

    • If you chose A: You added 25% of 90. The fall was 25% of the original, which is more than 90, so divide by 0.75. Go to M4.2.2.
    • If you chose B: You added 25 to 90. The fall is 25% of the original, not the number 25. Go to M4.2.2.
    • If you chose D: You took 25% off 90, which is a second fall. The original was bigger than 90. Go to M4.2.2.
  4. A rise of 20% is followed by a fall of 20%. Which single multiplier does the same job?

    A box Start joins to a box Up by an arrow labelled × 1.2. That box joins to a box Down by an arrow labelled × 0.8.Start× 1.2Up× 0.8Down
    Tap your answer.
    1. Yes, that is right. Multiply the two multipliers: 1.2 × 0.8 = 0.96.

    2. Not this one. A rise and a fall of the same percent do not cancel. The fall is a percent of a bigger amount than the rise. Go to M4.2.2. Try another.

    3. Not this one. This is the multiplier of the fall alone. The rise happened first, so multiply by 1.2 as well. Go to M4.2.2. Try another.

    See the answer

    0.96

    Multiply the two multipliers: 1.2 × 0.8 = 0.96.

    • If you chose B: A rise and a fall of the same percent do not cancel. The fall is a percent of a bigger amount than the rise. Go to M4.2.2.
    • If you chose C: This is the multiplier of the fall alone. The rise happened first, so multiply by 1.2 as well. Go to M4.2.2.
  5. An amount rises by 20% and then falls by 20%. Compared with the start, the end amount is:

    Tap your answer.
    1. Not this one. They do not cancel. The fall of 20% is taken from the bigger, risen amount, so it takes off more than the rise added. Go to M4.2.2. Try another.

    2. Not this one. The end multiplier is 0.96, which is below 1. An amount that has been multiplied by less than 1 is smaller. Go to M4.2.2. Try another.

    3. Not this one. The rise comes first and makes up for most of the fall. The end is much nearer the start than 20% less. Go to M4.2.2. Try another.

    4. Yes, that is right. The end is 1.2 × 0.8 = 0.96 of the start. That is 4% less.

    See the answer

    4% less than the start

    The end is 1.2 × 0.8 = 0.96 of the start. That is 4% less.

    • If you chose A: They do not cancel. The fall of 20% is taken from the bigger, risen amount, so it takes off more than the rise added. Go to M4.2.2.
    • If you chose B: The end multiplier is 0.96, which is below 1. An amount that has been multiplied by less than 1 is smaller. Go to M4.2.2.
    • If you chose C: The rise comes first and makes up for most of the fall. The end is much nearer the start than 20% less. Go to M4.2.2.
  6. From an earlier chapter

    Find the percentage change from 60 to 75. Type the number only.

    See the answer

    25

    The change is 75 − 60 = 15. Then 15 ÷ 60 × 100 = 25.

  7. After a 15% rise an amount is 345. Find the original amount.

    See the answer

    300

    A rise of 15% is a multiplier of 1.15. Divide to go back: 345 ÷ 1.15 = 300.

Keep it

Copy this into your exercise book.

To go back from a new amount, divide by the multiplier. Never take the same percent off the new amount. A rise then a fall of 10% gives 0.99.

Draw: Two boxes joined by an arrow labelled × 1.2 above and a return arrow labelled ÷ 1.2 below.

M4.2.3 Chapter 3

Simple and compound interest

Two savings clubs both add 5% a year to the coins I put in. Why does one of them give more?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

A saver puts 2 000 coins into a savings club. Each year the club adds interest, a percent of the savings. Here the rate is 4% a year.

Simple interest is the same amount every year. It is always 4% of the start amount. 4% of 2 000 is 80, so the saver gains 80 coins each year.

A table with the head Year, Interest, Total. Rows: 1, 80, 2 080; 2, 80, 2 160; 3, 80, 2 240; 4, 80, 2 320; 5, 80, 2 400.YearInterestTotal1802 0802802 1603802 2404802 3205802 400
Simple interest on 2 000 coins at 4% a year. The interest is the same every year.

Worked example

Work out the simple interest on 2 000 coins at 4% a year for 5 years.

  1. One year of interest: 4% of 2 000 = 0.04 × 2 000 = 80.
  2. 5 years of interest: 5 × 80 = 400.
  3. The total is 2 000 + 400 = 2 400 coins.

Answer: 400 coins of interest

To find simple interest, multiply the start amount by the rate as a decimal, and then by the number of years.

Compound interest is different. Each year the interest is worked out on the whole amount, including interest already added. The amount is multiplied by the same multiplier every year. For 5% the multiplier is 1.05.

A table with the head Year, Start, Added, End. Rows: 1, 8 000, 400, 8 400; 2, 8 400, 420, 8 820; 3, 8 820, 441, 9 261.YearStartAddedEnd18 0004008 40028 4004208 82038 8204419 261
8 000 coins at 5% compound interest. The interest grows because the start of each year is bigger.

Worked example

8 000 coins earn 5% compound interest a year. How many coins are there after 3 years?

  1. Each year the amount is multiplied by 1 + 0.05 = 1.05.
  2. After year 1: 8 000 × 1.05 = 8 400.
  3. After year 2: 8 400 × 1.05 = 8 820.
  4. After year 3: 8 820 × 1.05 = 9 261.

Answer: 9 261 coins

The three steps multiply by 1.05 three times. That is 1.05 × 1.05 × 1.05, written 1.05³. So the value after n years is the start amount times the multiplier, n times over.

See it three ways

With things

Put in 1 000 coins at 10% a year. After one year add a tenth: 1 100. After year two add a tenth of 1 100: 1 210.

As a picture

A box 1 000 joins to a box 1 100 by an arrow labelled × 1.1. That box joins to a box 1 210 by an arrow labelled × 1.1.1 000× 1.11 100× 1.11 210

In symbols

1 000 × 1.1 × 1.1 = 1 000 × 1.21 = 1 210.

Now compare the two over 10 years. Take 8 000 coins at 5% a year, both ways. In year 1 they are equal. After that, compound interest pulls ahead.

Draw it first

Simple and compound on one graph

  1. A graph with the x axis time (years) and the y axis value (thousands of coins). The y axis starts at 8, and a small zigzag next to the corner shows this. A straight line named simple rises steadily from 8 to 12. A curve named compound starts at the same point and bends upward to about 13.simple02468108101214time (years)value (thousands of coins)

    1 Simple interest adds the same amount each year, so its graph is a straight line.

  2. A graph with the x axis time (years) and the y axis value (thousands of coins). The y axis starts at 8, and a small zigzag next to the corner shows this. A straight line named simple rises steadily from 8 to 12. A curve named compound starts at the same point and bends upward to about 13.simplecompound02468108101214time (years)value (thousands of coins)

    2 Compound interest adds more each year, so its graph bends upward. The curve starts on the line, then rises above it.

A table with the head Year, Simple, Compound. Rows: 0, 8 000, 8 000; 1, 8 400, 8 400; 2, 8 800, 8 820; 3, 9 200, 9 261; 4, 9 600, 9 724; 5, 10 000, 10 210; 6, 10 400, 10 721; 7, 10 800, 11 257; 8, 11 200, 11 820; 9, 11 600, 12 411; 10, 12 000, 13 031.YearSimpleCompound08 0008 00018 4008 40028 8008 82039 2009 26149 6009 724510 00010 210610 40010 721710 80011 257811 20011 820911 60012 4111012 00013 031
Compound values are rounded to the nearest coin. The two match in year 1, and then the gap widens each year.

Worked example

8 000 coins earn 5% a year for 10 years. How many more coins does compound interest give than simple interest?

  1. Simple interest for 10 years: 8 000 × 0.05 × 10 = 4 000.
  2. So the simple total is 8 000 + 4 000 = 12 000.
  3. A calculator multiplies 8 000 by 1.05 ten times and gives 13 031, to the nearest coin.
  4. Compound gives more by 13 031 − 12 000 = 1 031.

Answer: 1 031 coins more

Try it

Make your own table

You need: paper, a pencil.

  1. Start with 1 000 coins and a rate of 10% a year. Draw three columns: year, simple and compound.
  2. For simple interest, add 100 each year.
  3. For compound interest, multiply the last amount by 1.1 each year. Round to the nearest coin.

What you will see: The two columns match in year 1. In year 2 compound is already ahead, with 1 210 against 1 200, and the gap grows.

If you cannot try it, this is what happens.
A table with the head Year, Simple, Compound. Rows: 0, 1 000, 1 000; 1, 1 100, 1 100; 2, 1 200, 1 210; 3, 1 300, 1 331; 4, 1 400, 1 464.YearSimpleCompound01 0001 00011 1001 10021 2001 21031 3001 33141 4001 464

A wrong idea many people have

8 000 coins at 5% compound interest for 3 years earns 3 × 5% = 15%, so the total is 9 200.

Why it feels right: Three years of 5% looks like 15%, and it is the answer simple interest would give.

The test that breaks it: Work year by year: 8 000 → 8 400 → 8 820 → 9 261. The total is 9 261, which is more than 9 200.

What is true: Each year's interest is worked out on a bigger amount. Multiply by 1.05 three times, not by 1.15 once.

Key words

interest
extra amount added to savings each year, worked out as a percent.
simple interest
interest that is always a percent of the start amount, so it is the same every year.
compound interest
interest worked out on the amount so far, including interest already added.

Back to your guess

The answer is A: One adds 5% of the start amount each year. The other adds 5% of the amount that has grown.

The rate can be the same and the totals still differ. Simple interest is always worked out on the start amount. Compound interest is worked out on the amount that has grown, so it earns interest on interest.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. Work out the simple interest on 2 500 coins at 6% a year for 4 years.

    Tap your answer.
    1. Not this one. This is one year of interest. Simple interest is the same every year, so multiply by the number of years, 4. Go to M4.2.3. Try another.

    2. Not this one. This is the compound interest, rounded. The question says simple, which is the same amount every year. Go to M4.2.3. Try another.

    3. Yes, that is right. One year: 6% of 2 500 = 150. For 4 years: 4 × 150 = 600.

    4. Not this one. This is the total, the start plus the interest. The question asks for the interest only. Go to M4.2.3. Try another.

    See the answer

    600

    One year: 6% of 2 500 = 150. For 4 years: 4 × 150 = 600.

    • If you chose A: This is one year of interest. Simple interest is the same every year, so multiply by the number of years, 4. Go to M4.2.3.
    • If you chose B: This is the compound interest, rounded. The question says simple, which is the same amount every year. Go to M4.2.3.
    • If you chose D: This is the total, the start plus the interest. The question asks for the interest only. Go to M4.2.3.
  2. 4 000 coins earn 5% compound interest a year. How many coins are there after 2 years?

    Tap your answer.
    1. Yes, that is right. Multiply by 1.05 twice: 4 000 × 1.05 = 4 200, and 4 200 × 1.05 = 4 410.

    2. Not this one. This is simple interest: 5% of 4 000 is 200 a year, and two years give 400. Compound interest works the second year on 4 200, not 4 000. Go to M4.2.3. Try another.

    3. Not this one. This is the amount after one year only. The question asks for two years, so multiply by 1.05 a second time. Go to M4.2.3. Try another.

    See the answer

    4 410

    Multiply by 1.05 twice: 4 000 × 1.05 = 4 200, and 4 200 × 1.05 = 4 410.

    • If you chose B: This is simple interest: 5% of 4 000 is 200 a year, and two years give 400. Compound interest works the second year on 4 200, not 4 000. Go to M4.2.3.
    • If you chose C: This is the amount after one year only. The question asks for two years, so multiply by 1.05 a second time. Go to M4.2.3.
  3. Which multiplier is used each year for 4% compound interest?

    Tap your answer.
    1. Not this one. This is 4% of the amount, which is the interest alone. The multiplier keeps the whole amount and adds the interest: 1 + 0.04. Go to M4.2.1. Try another.

    2. Yes, that is right. A rise of 4% each year is a multiplier of 1 + 0.04 = 1.04.

    3. Not this one. This is 1 + 0.4, a rise of 40%. A rise of 4% is 1 + 0.04. Go to M4.2.1. Try another.

    See the answer

    1.04

    A rise of 4% each year is a multiplier of 1 + 0.04 = 1.04.

    • If you chose A: This is 4% of the amount, which is the interest alone. The multiplier keeps the whole amount and adds the interest: 1 + 0.04. Go to M4.2.1.
    • If you chose C: This is 1 + 0.4, a rise of 40%. A rise of 4% is 1 + 0.04. Go to M4.2.1.
  4. The graph shows two plans that start with the same amount and the same rate. One adds simple interest and one adds compound interest. Which plan adds compound interest?

    A graph with the x axis time (years) and the y axis amount (hundreds of coins). The y axis starts at 10, and a small zigzag next to the corner shows this. A straight line is named Plan A. A curve that bends upward is named Plan B. Both start at the same point.Plan APlan B024681012141618202224time (years)amount (hundreds of coins)
    Tap your answer.
    1. Not this one. Plan A is a straight line: it adds the same amount each year, which is simple interest. Go to M4.2.3. Try another.

    2. Not this one. Only one graph bends. A graph that bends upward gains more each year than the year before, and that is compound. Go to M4.2.3. Try another.

    3. Not this one. You can. A straight line adds the same each year. A curve that rises faster and faster means interest on interest. Go to M4.2.3. Try another.

    4. Yes, that is right. Plan B bends upward, so it gains more each year than the year before. That is interest on interest, which is compound. Plan A is straight, so it adds the same each year.

    See the answer

    Plan B

    Plan B bends upward, so it gains more each year than the year before. That is interest on interest, which is compound. Plan A is straight, so it adds the same each year.

    • If you chose A: Plan A is a straight line: it adds the same amount each year, which is simple interest. Go to M4.2.3.
    • If you chose B: Only one graph bends. A graph that bends upward gains more each year than the year before, and that is compound. Go to M4.2.3.
    • If you chose C: You can. A straight line adds the same each year. A curve that rises faster and faster means interest on interest. Go to M4.2.3.
  5. Two savings clubs have the same start amount and the same rate. One adds simple interest and one adds compound interest. After one year, which club has more?

    Tap your answer.
    1. Not this one. In year 1 there is no interest yet to earn interest, so compound has nothing extra. The difference starts in year 2. Go to M4.2.3. Try another.

    2. Not this one. Simple is never ahead. In year 1 the two are equal, and after that compound is ahead. Go to M4.2.3. Try another.

    3. Yes, that is right. In year 1 both clubs work out the interest on the start amount, so they add the same. From year 2 the compound club earns interest on that interest as well.

    See the answer

    They have the same

    In year 1 both clubs work out the interest on the start amount, so they add the same. From year 2 the compound club earns interest on that interest as well.

    • If you chose A: In year 1 there is no interest yet to earn interest, so compound has nothing extra. The difference starts in year 2. Go to M4.2.3.
    • If you chose B: Simple is never ahead. In year 1 the two are equal, and after that compound is ahead. Go to M4.2.3.
  6. From an earlier chapter

    After a 20% fall an amount is 480 coins. What was it before? Type the number only.

    See the answer

    600

    A fall of 20% is a multiplier of 0.8. Divide to go back: 480 ÷ 0.8 = 600.

  7. Work out the simple interest on 3 000 coins at 3% a year for 4 years.

    See the answer

    360

    One year: 3% of 3 000 = 90. For 4 years: 4 × 90 = 360.

  8. A savings club adds 10% compound interest a year. How many coins are there after 2 years if 2 000 coins are put in?

    See the answer

    2 420

    Multiply by 1.1 twice: 2 000 × 1.1 = 2 200, and 2 200 × 1.1 = 2 420.

Keep it

Copy this into your exercise book.

Simple interest: start × rate × years, the same each year. Compound interest: multiply by 1 + rate once for every year. Compound is ahead after year 1.

Draw: A graph with a straight line named simple and a curve named compound above it.

M4.2.4 Chapter 4

Growth and decay

The fish in a lake fall by 15% every year. Will the lake ever have no fish at all?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

Ana studies a lake. It has 8 000 fish. Each year the number falls by 15%. How many fish are left after 3 years?

A fall of 15% leaves 85% of the fish. As a decimal that is 0.85. Each year the lake keeps 0.85 of what it had. So each year you multiply by 0.85 again.

Draw it first

Watch the fish fall

  1. A graph with the x axis time (years) and the y axis fish (thousands). Step 1 shows one dot at year 0, at 8. Step 2 adds dots at years 1, 2 and 3, each lower than the one before. Step 3 draws a curve named fish through them, falling fast at first and then more slowly.123456123456780time (years)fish (thousands)

    1 At the start the lake has 8 000 fish, which is 8 on this scale of thousands.

  2. A graph with the x axis time (years) and the y axis fish (thousands). Step 1 shows one dot at year 0, at 8. Step 2 adds dots at years 1, 2 and 3, each lower than the one before. Step 3 draws a curve named fish through them, falling fast at first and then more slowly.123456123456780time (years)fish (thousands)

    2 After 1, 2 and 3 years the dots are lower each time. The drops get smaller, because 15% of a smaller number is smaller.

  3. A graph with the x axis time (years) and the y axis fish (thousands). Step 1 shows one dot at year 0, at 8. Step 2 adds dots at years 1, 2 and 3, each lower than the one before. Step 3 draws a curve named fish through them, falling fast at first and then more slowly.fish123456123456780time (years)fish (thousands)

    3 The curve joins the dots. It falls fast at first, then more slowly, and it stays above zero.

A quantity that falls by the same percent every year is in decay. A quantity that rises by the same percent every year is in growth. Both are described by a model: a rule that says how the amount changes.

Worked example

A lake has 8 000 fish. The number falls by 15% each year. How many fish are there after 3 years?

  1. A fall of 15% leaves 85%, so the yearly multiplier is 0.85.
  2. After year 1: 8 000 × 0.85 = 6 800.
  3. After year 2: 6 800 × 0.85 = 5 780.
  4. After year 3: 5 780 × 0.85 = 4 913.

Answer: 4 913 fish

A table with the head Year, Fish. Rows: 0, 8 000; 1, 6 800; 2, 5 780; 3, 4 913; 4, 4 176; 5, 3 550; 6, 3 017.YearFish08 00016 80025 78034 91344 17653 55063 017
Each row is 8 000 × 0.85 once for every year, rounded to the nearest whole fish. The fall is 1 200 in year 1 but only 533 in year 6.

Growth works the same way, with a multiplier above 1. A herd of 100 goats grows by 10% each year. The yearly multiplier is 1 + 0.1 = 1.1.

A graph with the x axis time (years) and the y axis goats. A curve named herd starts at 100 and bends upward. A dot at year 5, named (5, 161), has dashed lines down to the x axis and across to the y axis.(5, 161)herd24681040801201602002400time (years)goats
Growth bends upward. Each year the herd gains more than the year before.

Worked example

A herd of 100 goats grows by 10% each year. How many goats are there after 5 years, to the nearest goat?

  1. A rise of 10% gives a yearly multiplier of 1.1.
  2. Five years means multiplying by 1.1 five times: 1.1⁵ = 1.61051.
  3. The herd is 100 × 1.61051 = 161.051.
  4. Goats are whole animals, so round to the nearest goat: 161.

Answer: 161 goats

The model gives parts of a goat. We compare the model's numbers with 150 and only round at the end.

Worked example

The same herd starts at 100 goats. In which year does it first pass 150 goats?

  1. Year 3 is below 150: 100 × 1.1³ = 133.1.
  2. Year 4 is below 150: 133.1 × 1.1 = 146.41.
  3. Year 5 is above 150: 146.41 × 1.1 = 161.051.
  4. So the herd first passes 150 goats in year 5. In year 5 the model gives 161.051, which is about 161 goats.

Answer: Year 5

See it three ways

With things

A herd of 100 goats. After one year add a tenth: 110. After year two add a tenth of that: 121.

As a picture

A box 100 joins to a box 110 by an arrow labelled × 1.1. That box joins to a box 121 by an arrow labelled × 1.1.100× 1.1110× 1.1121

In symbols

100 × 1.1 × 1.1 = 121.

Try it

Tear a strip of paper in half

You need: a strip of paper.

  1. Let the whole strip stand for 100%. Tear it in half and keep one piece.
  2. Tear the piece in half again and keep one piece. Do this three times in all.

What you will see: The pieces are 50%, 25% and 12.5% of the strip. Each tear multiplies by 0.5, a fall of 50%. In the model you can tear for ever and never reach nothing. A real strip becomes too small to tear.

If you cannot try it, this is what happens.
Four bars. The first is labelled Whole strip, with the label 100%. The second is labelled After 1 tear, with the label 50%. The third is labelled After 2 tears, with the label 25%. The fourth is labelled After 3 tears, with the label 12.5%. Each is half as long as the one before.Whole strip100%After 1 tear50%After 2 tears25%After 3 tears12.5%

A wrong idea many people have

A fall of 15% a year takes about 7 years to wipe out the fish, because 7 × 15% is about 100%.

Why it feels right: Seven falls of 15 take off about 100. That is right for 15 fish a year, but not for 15 percent.

The test that breaks it: A fall of 15% takes 15% of what is left, which gets smaller every year. After 7 years the lake still has about 2 565 of its 8 000 fish, which is 32%.

What is true: Multiply by 0.85 once for every year: 0.85 × 0.85 and so on. The number keeps falling but never reaches zero.

A wrong idea many people have

A rise of 10% a year for 2 years is a rise of 20%.

Why it feels right: Two lots of 10% add up to 20%, and the sum looks like the rule for simple interest.

The test that breaks it: Work it out for 100 goats. After 2 years the herd is 121, not 120. The second rise is 10% of the bigger herd.

What is true: Multiply the multipliers: 1.1 × 1.1 = 1.21. That is a rise of 21%.

Key words

decay
a fall by the same percent every period. The multiplier is below 1.
growth
a rise by the same percent every period. The multiplier is above 1.
model
a rule that says how an amount changes, such as multiplying by 0.85 every year.

Back to your guess

The answer is B: No. Each year it keeps 85% of the fish, so some always remain.

Each year the lake keeps 85% of the fish it had. Multiplying a number above zero by 0.85 never gives zero. In the model the fish get fewer and fewer, but never none. A real lake has whole fish, so the model is a guide while there are many.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. Which multiplier gives a fall of 8% each year?

    Tap your answer.
    1. Not this one. This is 8% of the amount, which is the size of the fall. The amount that is left is 100% − 8% = 92%. Go to M4.2.1. Try another.

    2. Not this one. This is the multiplier for a rise of 8%. A fall uses a multiplier below 1. Go to M4.2.1. Try another.

    3. Not this one. This is 80%, a fall of 20%. Read the decimal carefully: 8% leaves 92%, which is 0.92. Go to M4.2.1. Try another.

    4. Yes, that is right. A fall of 8% leaves 100% − 8% = 92%, which is 0.92 as a decimal.

    See the answer

    0.92

    A fall of 8% leaves 100% − 8% = 92%, which is 0.92 as a decimal.

    • If you chose A: This is 8% of the amount, which is the size of the fall. The amount that is left is 100% − 8% = 92%. Go to M4.2.1.
    • If you chose B: This is the multiplier for a rise of 8%. A fall uses a multiplier below 1. Go to M4.2.1.
    • If you chose C: This is 80%, a fall of 20%. Read the decimal carefully: 8% leaves 92%, which is 0.92. Go to M4.2.1.
  2. A herd of 200 goats grows by 10% each year. How many goats are there after 2 years?

    Tap your answer.
    1. Yes, that is right. 200 × 1.1 = 220 after one year, and 220 × 1.1 = 242 after two.

    2. Not this one. You added 10% of 200 twice. The second rise is 10% of the new herd, 220, not of 200. Go to M4.2.4. Try another.

    3. Not this one. This is the herd after one year. The question asks for two years, so multiply by 1.1 again. Go to M4.2.4. Try another.

    See the answer

    242

    200 × 1.1 = 220 after one year, and 220 × 1.1 = 242 after two.

    • If you chose B: You added 10% of 200 twice. The second rise is 10% of the new herd, 220, not of 200. Go to M4.2.4.
    • If you chose C: This is the herd after one year. The question asks for two years, so multiply by 1.1 again. Go to M4.2.4.
  3. An amount of 500 falls by 20% each year. What is it after 2 years?

    Tap your answer.
    1. Not this one. You took 20% of 500 off twice. The second fall is 20% of what is left after year 1, which is only 400. Go to M4.2.4. Try another.

    2. Not this one. This is the amount after one year. The question asks for two years, so multiply by 0.8 again. Go to M4.2.4. Try another.

    3. Yes, that is right. 500 × 0.8 = 400 after one year, and 400 × 0.8 = 320 after two.

    See the answer

    320

    500 × 0.8 = 400 after one year, and 400 × 0.8 = 320 after two.

    • If you chose A: You took 20% of 500 off twice. The second fall is 20% of what is left after year 1, which is only 400. Go to M4.2.4.
    • If you chose B: This is the amount after one year. The question asks for two years, so multiply by 0.8 again. Go to M4.2.4.
  4. The graph shows frogs in a pond. The number falls by 10% each year from 600. About how many frogs are there at point A, in year 4?

    A graph with the x axis time (years) and the y axis frogs. A falling curve named frogs starts at 600 and bends flat. A dot named A at year 4 has dashed lines down to the x axis and across to the y axis.Afrogs24681002003004005006000time (years)frogs
    Tap your answer.
    1. Not this one. You took 10% of 600 off four times, which is 60 each time. Each fall is 10% of what is left, so the falls get smaller. Go to M4.2.4. Try another.

    2. Yes, that is right. The multiplier is 0.9. Four years: 600 × 0.9⁴ = 393.66, which is about 394 frogs.

    3. Not this one. This is the number after one year. Point A is in year 4, after four falls. Go to M4.2.4. Try another.

    4. Not this one. This is the number after three years. Point A is in year 4, so multiply by 0.9 once more. Go to M4.2.4. Try another.

    See the answer

    394

    The multiplier is 0.9. Four years: 600 × 0.9⁴ = 393.66, which is about 394 frogs.

    • If you chose A: You took 10% of 600 off four times, which is 60 each time. Each fall is 10% of what is left, so the falls get smaller. Go to M4.2.4.
    • If you chose C: This is the number after one year. Point A is in year 4, after four falls. Go to M4.2.4.
    • If you chose D: This is the number after three years. Point A is in year 4, so multiply by 0.9 once more. Go to M4.2.4.
  5. Fish in a lake fall by 15% each year in the model. Will the number of fish ever reach exactly zero?

    Tap your answer.
    1. Yes, that is right. Each year the number is multiplied by 0.85. A number above zero multiplied by 0.85 is still above zero. So the model never reaches zero.

    2. Not this one. Seven falls of 15% do not add up to 100%. Each fall is 15% of what is left, which is smaller each year. After 7 years about a third of the fish remain. Go to M4.2.4. Try another.

    3. Not this one. There is no year when the multiplier 0.85 makes the number zero. A number above zero times 0.85 is still above zero. Go to M4.2.4. Try another.

    See the answer

    No. It gets smaller each year but never reaches zero.

    Each year the number is multiplied by 0.85. A number above zero multiplied by 0.85 is still above zero. So the model never reaches zero.

    • If you chose B: Seven falls of 15% do not add up to 100%. Each fall is 15% of what is left, which is smaller each year. After 7 years about a third of the fish remain. Go to M4.2.4.
    • If you chose C: There is no year when the multiplier 0.85 makes the number zero. A number above zero times 0.85 is still above zero. Go to M4.2.4.
  6. From an earlier chapter

    Work out the simple interest on 2 500 coins at 4% a year for 3 years.

    See the answer

    300

    One year: 4% of 2 500 = 100. For 3 years: 3 × 100 = 300.

  7. A herd of 300 goats grows by 10% each year. How many goats are there after 2 years?

    See the answer

    363

    300 × 1.1 = 330 after one year, and 330 × 1.1 = 363 after two.

  8. The number of fish falls by 20% each year from 1 000. How many fish are there after 3 years?

    See the answer

    512

    The multiplier is 0.8. 1 000 × 0.8 = 800, then 800 × 0.8 = 640, then 640 × 0.8 = 512.

Keep it

Copy this into your exercise book.

A fall of p% a year multiplies by 1 − p/100 every year. A rise multiplies by 1 + p/100. Decay stays above zero. Growth bends upward.

Draw: A falling curve that flattens and a rising curve that steepens, each with its multiplier written beside it.

M4.2.5 Chapter 5

Harder ratio problems

Mei and Ana share beads in the ratio 2 : 3. Ana and Tariq share beads in the ratio 4 : 5. What is the ratio of all three?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

Mei and Ana share beads in the ratio 2 : 3. Ana and Tariq share beads in the ratio 4 : 5. Ana appears in both ratios. We want one ratio for all three.

Ana is 3 parts in the first ratio and 4 parts in the second. Those are different sizes of part, so we cannot join the numbers yet. First we make Ana the same in both.

Draw it first

Make the middle the same

  1. Two small pairs of bars. The first pair is Mei: 2 parts and Ana: 3 parts, each part 4 pieces wide. The second pair is Ana: 4 parts and Tariq: 5 parts, each part 3 pieces wide. In step 3 four bars of the same lengths show the pieces: Mei: 8 pieces, Ana, first ratio: 12 pieces, Ana, second ratio: 12 pieces, Tariq: 15 pieces. Thick lines cut the bars into groups.Mei: 2 partsAna: 3 parts

    1 Mei and Ana: 2 parts to 3 parts. Ana has 3 parts here.

  2. Two small pairs of bars. The first pair is Mei: 2 parts and Ana: 3 parts, each part 4 pieces wide. The second pair is Ana: 4 parts and Tariq: 5 parts, each part 3 pieces wide. In step 3 four bars of the same lengths show the pieces: Mei: 8 pieces, Ana, first ratio: 12 pieces, Ana, second ratio: 12 pieces, Tariq: 15 pieces. Thick lines cut the bars into groups.Mei: 2 partsAna: 3 partsAna: 4 partsTariq: 5 parts

    2 Ana and Tariq: 4 parts to 5 parts. Ana has 4 parts here, a different size of part.

  3. Two small pairs of bars. The first pair is Mei: 2 parts and Ana: 3 parts, each part 4 pieces wide. The second pair is Ana: 4 parts and Tariq: 5 parts, each part 3 pieces wide. In step 3 four bars of the same lengths show the pieces: Mei: 8 pieces, Ana, first ratio: 12 pieces, Ana, second ratio: 12 pieces, Tariq: 15 pieces. Thick lines cut the bars into groups.Mei: 8 piecesAna, first ratio: 12 piecesAna, second ratio: 12 piecesTariq: 15 pieces

    3 Cut each part into smaller equal pieces. Ana's bar keeps its length. Make Ana 12 pieces in both. Mei is then 8 pieces and Tariq is 15 pieces.

Multiplying both numbers of a ratio by the same number gives an equal ratio. 2 : 3 = 8 : 12 when you multiply by 4. Pick the numbers so Ana matches: the lowest common multiple of 3 and 4, which is 12.

Worked example

Mei : Ana is 2 : 3 and Ana : Tariq is 4 : 5. Find Mei : Ana : Tariq.

  1. Ana has 3 parts in the first ratio and 4 parts in the second.
  2. The lowest common multiple of 3 and 4 is 12. Make Ana 12 in both.
  3. First ratio, multiply by 4: 2 : 3 = 8 : 12.
  4. Second ratio, multiply by 3: 4 : 5 = 12 : 15.
  5. Ana is 12 in both, so Mei : Ana : Tariq = 8 : 12 : 15.

Answer: 8 : 12 : 15

With a : b : c you can share an amount. Add the parts to find how many equal shares there are. Then find one part, and multiply.

Three bars of equal blocks with the number 2 in every block. Mei: 8 parts, Ana: 12 parts and Tariq: 15 parts. Each block stands for 2 beads.Mei: 8 parts22222222Ana: 12 parts222222222222Tariq: 15 parts222222222222222
70 beads in 35 parts. Each part is 2 beads.

Worked example

Mei, Ana and Tariq have 70 beads together in the ratio 8 : 12 : 15. How many beads does each have?

  1. Add the parts: 8 + 12 + 15 = 35.
  2. One part is 70 ÷ 35 = 2 beads.
  3. Mei has 8 × 2 = 16, Ana has 12 × 2 = 24, and Tariq has 15 × 2 = 30.
  4. Check: 16 + 24 + 30 = 70.

Answer: 16, 24 and 30 beads

Now a different kind of problem. Some are added, and the ratio changes. One group stays the same size. That group gives you the key.

Three bars of equal blocks. Goats, both times: 3 parts, Sheep before: 2 parts, and Sheep after: 5 parts where the last 3 blocks are dotted because they were added.Goats, both times: 3 partsSheep before: 2 partsSheep after: 5 parts
The goats stay 3 parts. The sheep go from 2 parts to 5 parts. The dotted parts are the 12 sheep that were added.

Worked example

Kofi has goats and sheep in the ratio 3 : 2. He gets 12 more sheep, and now goats : sheep is 3 : 5. How many of each did he have at the start?

  1. The goats did not change, so 3 parts of goats keep the same size.
  2. The sheep went from 2 parts to 5 parts. That is 5 − 2 = 3 more parts.
  3. The 3 more parts are 12 sheep, so one part is 12 ÷ 3 = 4.
  4. At the start: goats 3 × 4 = 12, and sheep 2 × 4 = 8.
  5. Check: after, 12 goats and 8 + 12 = 20 sheep, and 12 : 20 = 3 : 5.

Answer: 12 goats and 8 sheep

See it three ways

With things

Mei has 2 beads for every 3 of Ana's. Put 4 such sets together. Mei has 8 beads and Ana has 12.

As a picture

Two bars. Mei: 8 parts is cut into 4 groups of 2 blocks. Ana: 12 parts is cut into 4 groups of 3 blocks.Mei: 8 partsAna: 12 parts

In symbols

2 : 3 = 8 : 12.

Try it

Check with stones

You need: 35 stones or beans.

  1. Lay out 8 stones for Mei, 12 for Ana and 15 for Tariq, in three rows.
  2. Group Mei's and Ana's stones in fours. Count the groups. Then group Ana's and Tariq's stones in threes, and count again.

What you will see: In fours, Mei has 2 groups and Ana has 3, so Mei : Ana is 2 : 3. In threes, Ana has 4 groups and Tariq has 5, so Ana : Tariq is 4 : 5.

If you cannot try it, this is what happens.
Four bars. Mei: 8 parts, Ana, first ratio: 12 parts, Ana, second ratio: 12 parts, Tariq: 15 parts. The first two are cut into groups of 4 blocks and the last two into groups of 3 blocks.Mei: 8 partsAna, first ratio: 12 partsAna, second ratio: 12 partsTariq: 15 parts

A wrong idea many people have

Mei : Ana is 2 : 3 and Ana : Tariq is 4 : 5, so Mei : Ana : Tariq is 2 : 3 : 5.

Why it feels right: The names Mei, Ana and Tariq come in order, and so it looks as if the numbers can come in order too.

The test that breaks it: In 2 : 3 : 5, Ana : Tariq would be 3 : 5. The question says Ana : Tariq is 4 : 5. That does not match.

What is true: The shared person must have the same number in both ratios. Make Ana 12 in both first, then join.

A wrong idea many people have

Goats : sheep is 3 : 2. Adding 12 sheep makes it 3 : 14.

Why it feels right: The sheep number in the ratio is 2, and 12 sheep are added, so 2 + 12 looks right.

The test that breaks it: The 2 in the ratio is 2 parts, not 2 sheep. A part is not the same size as one sheep. You cannot add 12 sheep to 2 parts.

What is true: Find how big one part is first. Here one part is 4 sheep, so 12 sheep are 3 parts.

Key words

lowest common multiple
the smallest whole number above 0 that both numbers divide into. For 3 and 4 it is 12.

Back to your guess

The answer is C: Mei : Ana : Tariq is 8 : 12 : 15.

Ana has 3 parts in one ratio and 4 parts in the other, so the numbers cannot just be joined. Make Ana the same in both: 12. Then 2 : 3 becomes 8 : 12, and 4 : 5 becomes 12 : 15. So Mei : Ana : Tariq is 8 : 12 : 15.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. A : B is 3 : 4 and B : C is 2 : 5. What is A : B : C?

    Tap your answer.
    1. Not this one. You joined the numbers without matching B. B is 4 in the first ratio and 2 in the second, so they are not the same size of part. Go to M4.2.5. Try another.

    2. Yes, that is right. B is 4 and 2. The lowest common multiple is 4. The first ratio stays 3 : 4. The second, multiplied by 2, is 4 : 10. So A : B : C is 3 : 4 : 10.

    3. Not this one. You doubled the first ratio but not the second. B is 8 in the first, and 2 in the second, which is not 8. Scale both ratios. Go to M4.2.5. Try another.

    4. Not this one. You took A from the first ratio and B : C from the second. B is 4 in one and 2 in the other, so the parts are different sizes. Make B the same first. Go to M4.2.5. Try another.

    See the answer

    3 : 4 : 10

    B is 4 and 2. The lowest common multiple is 4. The first ratio stays 3 : 4. The second, multiplied by 2, is 4 : 10. So A : B : C is 3 : 4 : 10.

    • If you chose A: You joined the numbers without matching B. B is 4 in the first ratio and 2 in the second, so they are not the same size of part. Go to M4.2.5.
    • If you chose C: You doubled the first ratio but not the second. B is 8 in the first, and 2 in the second, which is not 8. Scale both ratios. Go to M4.2.5.
    • If you chose D: You took A from the first ratio and B : C from the second. B is 4 in one and 2 in the other, so the parts are different sizes. Make B the same first. Go to M4.2.5.
  2. A : B is 2 : 5 and B : C is 10 : 3. What is A : B : C?

    Tap your answer.
    1. Not this one. You joined the numbers without matching B. B is 5 in the first ratio and 10 in the second. Go to M4.2.5. Try another.

    2. Not this one. You took B from the second ratio but did not scale A with it. If B doubles from 5 to 10, A must double too. Go to M4.2.5. Try another.

    3. Not this one. You doubled A but kept B at 5. Doubling the first ratio makes 4 : 10, so B must be 10. Go to M4.2.5. Try another.

    4. Yes, that is right. B is 5 and 10. The lowest common multiple is 10. The first ratio, multiplied by 2, is 4 : 10. The second ratio stays 10 : 3. So A : B : C is 4 : 10 : 3.

    See the answer

    4 : 10 : 3

    B is 5 and 10. The lowest common multiple is 10. The first ratio, multiplied by 2, is 4 : 10. The second ratio stays 10 : 3. So A : B : C is 4 : 10 : 3.

    • If you chose A: You joined the numbers without matching B. B is 5 in the first ratio and 10 in the second. Go to M4.2.5.
    • If you chose B: You took B from the second ratio but did not scale A with it. If B doubles from 5 to 10, A must double too. Go to M4.2.5.
    • If you chose C: You doubled A but kept B at 5. Doubling the first ratio makes 4 : 10, so B must be 10. Go to M4.2.5.
  3. Share 90 beads in the ratio 2 : 3 : 4. How many beads is the largest share?

    Tap your answer.
    1. Yes, that is right. The parts add up to 2 + 3 + 4 = 9. One part is 90 ÷ 9 = 10. The largest share is 4 × 10 = 40.

    2. Not this one. This is the middle share, 3 parts. The largest share is the 4 parts. Go to M3.4.3. Try another.

    3. Not this one. This is the size of one part, 90 ÷ 9. The largest share is 4 of those parts. Go to M3.4.3. Try another.

    4. Not this one. You divided 90 by 4, the largest number in the ratio. Divide by the total of the parts, 2 + 3 + 4 = 9, then take 4 of them. Go to M3.4.3. Try another.

    See the answer

    40

    The parts add up to 2 + 3 + 4 = 9. One part is 90 ÷ 9 = 10. The largest share is 4 × 10 = 40.

    • If you chose B: This is the middle share, 3 parts. The largest share is the 4 parts. Go to M3.4.3.
    • If you chose C: This is the size of one part, 90 ÷ 9. The largest share is 4 of those parts. Go to M3.4.3.
    • If you chose D: You divided 90 by 4, the largest number in the ratio. Divide by the total of the parts, 2 + 3 + 4 = 9, then take 4 of them. Go to M3.4.3.
  4. Red and blue beads are in the ratio 2 : 3. After 10 more blue beads are added, the ratio is 2 : 5. How many red beads are there?

    Tap your answer.
    1. Not this one. This is the size of one part. There are 2 parts of red, so red is 2 × 5. Go to M4.2.5. Try another.

    2. Not this one. This is the number of blue beads at the start, 3 parts. The question asks for red. Go to M4.2.5. Try another.

    3. Yes, that is right. The red beads did not change. Blue went from 3 parts to 5 parts, which is 2 more parts. So 2 parts are 10 beads, and one part is 5. Red is 2 parts, so 2 × 5 = 10.

    4. Not this one. This is the number of blue beads at the end, 5 parts. The question asks for red. Go to M4.2.5. Try another.

    See the answer

    10

    The red beads did not change. Blue went from 3 parts to 5 parts, which is 2 more parts. So 2 parts are 10 beads, and one part is 5. Red is 2 parts, so 2 × 5 = 10.

    • If you chose A: This is the size of one part. There are 2 parts of red, so red is 2 × 5. Go to M4.2.5.
    • If you chose B: This is the number of blue beads at the start, 3 parts. The question asks for red. Go to M4.2.5.
    • If you chose D: This is the number of blue beads at the end, 5 parts. The question asks for red. Go to M4.2.5.
  5. The bars show A, B and C. What is the ratio A : B : C in its simplest form?

    Three bars of equal blocks. A: 4 blocks, B: 6 blocks, C: 10 blocks.A: 4 blocksB: 6 blocksC: 10 blocks
    Tap your answer.
    1. Not this one. This is a true ratio for the bars, but not the simplest. Divide each number by 2 to get the simplest form. Go to M3.4.1. Try another.

    2. Yes, that is right. The bars hold 4, 6 and 10 blocks. All three divide by 2, giving 2, 3 and 5. No bigger number divides all three, so 2 : 3 : 5 is simplest.

    3. Not this one. This is the right numbers in the wrong order. A is the first bar, so its number comes first. Go to M3.4.1. Try another.

    See the answer

    2 : 3 : 5

    The bars hold 4, 6 and 10 blocks. All three divide by 2, giving 2, 3 and 5. No bigger number divides all three, so 2 : 3 : 5 is simplest.

    • If you chose A: This is a true ratio for the bars, but not the simplest. Divide each number by 2 to get the simplest form. Go to M3.4.1.
    • If you chose C: This is the right numbers in the wrong order. A is the first bar, so its number comes first. Go to M3.4.1.
  6. From an earlier chapter

    After a 20% rise an amount is 180. What was it before? Type the number only.

    See the answer

    150

    A rise of 20% is a multiplier of 1.2. Divide to go back: 180 ÷ 1.2 = 150.

  7. Share 84 stones in the ratio 1 : 2 : 4. How many stones is the largest share?

    See the answer

    48

    The parts add up to 1 + 2 + 4 = 7. One part is 84 ÷ 7 = 12. The largest share is 4 × 12 = 48.

  8. A : B is 3 : 5 and B : C is 10 : 7. Write A : B : C. Type the three numbers.

    See the answer

    6 : 10 : 7

    B is 5 and 10. The lowest common multiple is 10. The first ratio, multiplied by 2, is 6 : 10. The second stays 10 : 7. So A : B : C is 6 : 10 : 7.

Keep it

Copy this into your exercise book.

To join a : b and b : c, make b the same in both with the lowest common multiple. When some are added, find what stayed the same, then the size of one part.

Draw: Two pairs of bars with the shared bar cut into 12 equal pieces, and the joined bars 8 : 12 : 15 beneath.

M4.2.6 Chapter 6

Proportion as a formula

If y is proportional to x, how do I write that as a formula?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

A tap fills 5 litres every minute. After 1 minute there are 5 litres. After 2 minutes there are 10. After 3 minutes there are 15. Each time, the litres are the minutes times 5.

Draw it first

Every y is x times the same number

  1. Three rows, each a box joined to a box by an arrow labelled × 5: x = 1 min to y = 5 litres, x = 2 min to y = 10 litres, and x = 3 min to y = 15 litres. Then the formula y = 5x.x = 1 min× 5y = 5 litres

    1 After 1 minute, y is 1 × 5 = 5.

  2. Three rows, each a box joined to a box by an arrow labelled × 5: x = 1 min to y = 5 litres, x = 2 min to y = 10 litres, and x = 3 min to y = 15 litres. Then the formula y = 5x.x = 1 min× 5y = 5 litresx = 2 min× 5y = 10 litres

    2 After 2 minutes, y is 2 × 5 = 10.

  3. Three rows, each a box joined to a box by an arrow labelled × 5: x = 1 min to y = 5 litres, x = 2 min to y = 10 litres, and x = 3 min to y = 15 litres. Then the formula y = 5x.x = 1 min× 5y = 5 litresx = 2 min× 5y = 10 litresx = 3 min× 5y = 15 litres

    3 After 3 minutes, y is 3 × 5 = 15.

  4. Three rows, each a box joined to a box by an arrow labelled × 5: x = 1 min to y = 5 litres, x = 2 min to y = 10 litres, and x = 3 min to y = 15 litres. Then the formula y = 5x.x = 1 min× 5y = 5 litresx = 2 min× 5y = 10 litresx = 3 min× 5y = 15 litresy = 5x

    4 The same number 5 multiplies every x. We write the rule as a formula: y = 5x.

We say y is directly proportional to x, or just proportional. It means y = kx, where k is a fixed number that never changes. The number k is the constant of proportionality. Here k = 5. It must not be 0.

To find k, take any pair of values and divide: k = y ÷ x. Then k stays the same for every pair.

A table with the head x, y, y ÷ x. Rows: 1, 5, 5; 2, 10, 5; 3, 15, 5.xyy ÷ x15521053155
The last column is always 5. That is how you know y is proportional to x.

Worked example

y is proportional to x. When x = 7, y = 35. Find the formula, and find y when x = 12.

  1. Write the formula y = kx.
  2. Put in x = 7 and y = 35: 35 = k × 7, so k = 35 ÷ 7 = 5.
  3. The formula is y = 5x.
  4. When x = 12, y = 5 × 12 = 60.

Answer: y = 5x. When x = 12, y = 60.

Some things grow faster than that. Take a right-angled triangle whose two shorter sides are both x cm. Its area is half of x times x. When x doubles, the area does not double. It becomes four times as big.

Two squares of tiles. The first has 2 tiles along each side and is labelled 4 tiles. The second has 4 tiles along each side and is labelled 16 tiles. The side is doubled, and the area is four times as big.224 tiles4416 tiles
Double the side and the area is 2 × 2 = 4 times as big.

When y is proportional to x², the formula is y = kx². For the triangle, y = 0.5x². Doubling x multiplies y by 2² = 4.

A table with the head x (cm), y (cm²). Rows: 2, 2; 4, 8; 6, 18.x (cm)y (cm²)2248618
The area y cm² of a right-angled triangle with two sides of x cm. Going from x = 2 to x = 4 multiplies y by 4. Going to x = 6 multiplies it by 9.
A right-angled triangle with its two shorter sides labelled 6 cm and 6 cm, and the label area 18 cm² under it. Beside it is a square of tiles, 6 tiles along each side, labelled 6, 6 and 36 tiles. The triangle is half of the square.6 cm6 cmarea 18 cm²6636 tiles
A right-angled triangle with two sides of 6 cm is half of a 6 cm by 6 cm square. The square holds 36 tiles of 1 cm², so the triangle has an area of 18 cm².

Worked example

A right-angled triangle has two equal shorter sides of x cm. Its area y cm² is proportional to x². When x = 6, y = 18. Find y when x = 10.

  1. Write the formula y = kx².
  2. Put in x = 6 and y = 18: 18 = k × 6², so k = 18 ÷ 36 = 0.5.
  3. The formula is y = 0.5x².
  4. When x = 10, y = 0.5 × 10² = 0.5 × 100 = 50.

Answer: y = 0.5x². When x = 10, y = 50.

The other kind goes the opposite way. A 120 km journey takes 3 hours at 40 km per hour. At twice the speed it takes half the time. The time y hours is 120 divided by the speed x.

We say y is inversely proportional to x, or proportional to 1/x. The formula is y = k ÷ x. Multiply x and y and you always get k. Here x is a speed, so it is above 0.

A table with the head km/h, Hours, Distance (km). Rows: 20, 6, 120; 40, 3, 120; 60, 2, 120; 80, 1.5, 120.km/hHoursDistance (km)206120403120602120801.5120
Speed is in km per hour. The last column is always 120 km. When the speed goes up, the time goes down.

Worked example

The time y hours for a journey is inversely proportional to the speed x km per hour. At 40 km per hour it takes 3 hours. How long does it take at 60 km per hour?

  1. Time is proportional to 1 ÷ speed, so y = k ÷ x.
  2. At 40 km per hour the time is 3 hours: 3 = k ÷ 40.
  3. Multiply both sides by 40: k = 3 × 40 = 120.
  4. The formula is y = 120 ÷ x. Check: 120 ÷ 40 = 3.
  5. At 60 km per hour: y = 120 ÷ 60 = 2.

Answer: 2 hours

See it three ways

With things

A tap fills 5 litres each minute. After 1 minute: 5 litres. After 2 minutes: 10. After 3 minutes: 15.

As a picture

A table with the head Minutes, Litres. Rows: 1, 5; 2, 10; 3, 15; 4, 20.MinutesLitres15210315420

In symbols

y = 5x.

Try it

Rectangles of the same area

You need: squared paper, a pencil.

  1. Draw a rectangle 1 square across and 12 squares up. It holds 12 squares.
  2. Draw more rectangles that also hold 12 squares: 2 across, 3 across, 4 across. Write how many squares go up each time.

What you will see: As the number across goes up, the number up goes down. Across times up is always 12. That is inverse proportion.

If you cannot try it, this is what happens.
A table with the head Across, Up, Squares. Rows: 1, 12, 12; 2, 6, 12; 3, 4, 12; 4, 3, 12; 6, 2, 12.AcrossUpSquares112122612341243126212

A wrong idea many people have

If y is proportional to x², then doubling x doubles y.

Why it feels right: Proportional usually means "when one doubles, the other doubles", and that is how direct proportion works.

The test that breaks it: Take y = 0.5x². When x = 2, y = 2. When x = 4, which is double, y = 8. That is four times as big, not double.

What is true: When y is proportional to x², doubling x multiplies y by 2² = 4. Tripling x multiplies y by 9.

A wrong idea many people have

Inverse proportion means y goes down by the same amount that x goes up.

Why it feels right: One goes up and the other goes down, so it feels as if they trade places evenly.

The test that breaks it: Take y = 24 ÷ x. When x = 4, y = 6. When x = 8, y = 3, which is a fall of 3. When x = 12, y = 2, which is a fall of only 1.

What is true: When x is multiplied by a number, y is divided by the same number. Then x times y stays the same.

Key words

directly proportional
y = kx for a fixed number k. Doubling x doubles y.
constant of proportionality
the fixed number k in y = kx or y = k ÷ x.
inversely proportional
y = k ÷ x for a fixed number k. Doubling x halves y.

Back to your guess

The answer is A: y = kx, where k is a fixed number.

Proportional means y is always the same multiple of x. Double x and y doubles. So y = kx, with k a fixed number. The formula y = k ÷ x is for inverse proportion, where doubling x halves y.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. y is proportional to x. When x = 4, y = 28. Which formula is right?

    Tap your answer.
    1. Not this one. This fits x = 4, y = 28, but adding is not proportion. When x doubles to 8 this gives 32, and y should double to 56. Go to M4.2.6. Try another.

    2. Not this one. You used the value of x as k. The number k is y ÷ x, which is 28 ÷ 4. Go to M4.2.6. Try another.

    3. Not this one. You multiplied 4 by 28. To find k you divide y by x. Go to M4.2.6. Try another.

    4. Yes, that is right. k = y ÷ x = 28 ÷ 4 = 7. So y = 7x.

    See the answer

    y = 7x

    k = y ÷ x = 28 ÷ 4 = 7. So y = 7x.

    • If you chose A: This fits x = 4, y = 28, but adding is not proportion. When x doubles to 8 this gives 32, and y should double to 56. Go to M4.2.6.
    • If you chose B: You used the value of x as k. The number k is y ÷ x, which is 28 ÷ 4. Go to M4.2.6.
    • If you chose C: You multiplied 4 by 28. To find k you divide y by x. Go to M4.2.6.
  2. y is proportional to x. When x = 4, y = 10. Find y when x = 10.

    Tap your answer.
    1. Yes, that is right. k = 10 ÷ 4 = 2.5. Then y = 2.5 × 10 = 25.

    2. Not this one. You added 6 to y because x went up by 6. Proportion multiplies: y is always the same number times x. Go to M4.2.6. Try another.

    3. Not this one. You multiplied 10 by 10. First find k = y ÷ x = 10 ÷ 4, then multiply k by the new x. Go to M4.2.6. Try another.

    See the answer

    25

    k = 10 ÷ 4 = 2.5. Then y = 2.5 × 10 = 25.

    • If you chose B: You added 6 to y because x went up by 6. Proportion multiplies: y is always the same number times x. Go to M4.2.6.
    • If you chose C: You multiplied 10 by 10. First find k = y ÷ x = 10 ÷ 4, then multiply k by the new x. Go to M4.2.6.
  3. y is proportional to x². When x = 2, y = 12. Find y when x = 4.

    Tap your answer.
    1. Not this one. You doubled y because x doubled. That is direct proportion with x. Here y is proportional to x², so doubling x makes y four times as big. Go to M4.2.6. Try another.

    2. Not this one. You multiplied 12 by 4². But y = 12 already includes the 2². Find k first: k = 12 ÷ 2², then use k × 4². Go to M4.2.6. Try another.

    3. Yes, that is right. k = 12 ÷ 2² = 3. Then y = 3 × 4² = 3 × 16 = 48.

    See the answer

    48

    k = 12 ÷ 2² = 3. Then y = 3 × 4² = 3 × 16 = 48.

    • If you chose A: You doubled y because x doubled. That is direct proportion with x. Here y is proportional to x², so doubling x makes y four times as big. Go to M4.2.6.
    • If you chose B: You multiplied 12 by 4². But y = 12 already includes the 2². Find k first: k = 12 ÷ 2², then use k × 4². Go to M4.2.6.
  4. y is inversely proportional to x. When x = 4, y = 6. Find y when x = 8.

    Tap your answer.
    1. Not this one. You doubled y because x doubled. In inverse proportion, doubling x halves y. Go to M4.2.6. Try another.

    2. Yes, that is right. k = x × y = 4 × 6 = 24. Then y = 24 ÷ 8 = 3.

    3. Not this one. You took 4 away from 6 because x went up by 4. Inverse proportion divides: x times y stays the same. Go to M4.2.6. Try another.

    See the answer

    3

    k = x × y = 4 × 6 = 24. Then y = 24 ÷ 8 = 3.

    • If you chose A: You doubled y because x doubled. In inverse proportion, doubling x halves y. Go to M4.2.6.
    • If you chose C: You took 4 away from 6 because x went up by 4. Inverse proportion divides: x times y stays the same. Go to M4.2.6.
  5. A tank fills at 12 litres a minute and is full after 5 minutes. The time is inversely proportional to the speed. How long does it take at 15 litres a minute?

    Tap your answer.
    1. Yes, that is right. The tank holds 12 × 5 = 60 litres. At 15 litres a minute it takes 60 ÷ 15 = 4 minutes.

    2. Not this one. You multiplied the time by 15 ÷ 12, as if it were direct proportion. A faster tap needs less time, not more. Go to M4.2.6. Try another.

    3. Not this one. You took 3 away from 5 because the tap is 3 litres faster. Inverse proportion divides: k = 12 × 5 = 60 litres, so the time is 60 ÷ 15. Go to M4.2.6. Try another.

    See the answer

    4 minutes

    The tank holds 12 × 5 = 60 litres. At 15 litres a minute it takes 60 ÷ 15 = 4 minutes.

    • If you chose B: You multiplied the time by 15 ÷ 12, as if it were direct proportion. A faster tap needs less time, not more. Go to M4.2.6.
    • If you chose C: You took 3 away from 5 because the tap is 3 litres faster. Inverse proportion divides: k = 12 × 5 = 60 litres, so the time is 60 ÷ 15. Go to M4.2.6.
  6. y is proportional to x². When x = 3, y = 36. Which formula is right?

    Tap your answer.
    1. Not this one. You divided y by x, not by x². That gives k for y = kx, which is direct proportion with x. Here y is proportional to x². Go to M4.2.6. Try another.

    2. Not this one. You used x² itself as k. The number k is y ÷ x², which is 36 ÷ 9. Go to M4.2.6. Try another.

    3. Yes, that is right. k = y ÷ x² = 36 ÷ 3² = 36 ÷ 9 = 4. So y = 4x².

    See the answer

    y = 4x²

    k = y ÷ x² = 36 ÷ 3² = 36 ÷ 9 = 4. So y = 4x².

    • If you chose A: You divided y by x, not by x². That gives k for y = kx, which is direct proportion with x. Here y is proportional to x². Go to M4.2.6.
    • If you chose B: You used x² itself as k. The number k is y ÷ x², which is 36 ÷ 9. Go to M4.2.6.
  7. From an earlier chapter

    The number of goats falls by 20% each year from 400. How many goats are there after 2 years?

    See the answer

    256

    The multiplier is 0.8. 400 × 0.8 = 320 after one year, and 320 × 0.8 = 256 after two.

  8. y is proportional to x. When x = 6, y = 18. Find y when x = 15.

    See the answer

    45

    k = 18 ÷ 6 = 3. Then y = 3 × 15 = 45.

  9. y is proportional to x². When x = 3, y = 27. Find y when x = 5.

    See the answer

    75

    k = 27 ÷ 3² = 27 ÷ 9 = 3. Then y = 3 × 5² = 3 × 25 = 75.

Keep it

Copy this into your exercise book.

Proportional to x: y = kx, and y ÷ x is always k. Proportional to x²: y = kx². Inversely proportional to x: y = k ÷ x, and x times y is always k.

Draw: Three small tables, one for each kind, with the column y ÷ x, y ÷ x² or x × y beside each.

M4.2.7 Chapter 7

Graphs of proportion

How can I tell from a graph that two amounts are in proportion?

Your guess

Pick one before you read on. It is fine to be wrong.

Your guess
  • You picked A. Read on. At the end, the chapter comes back to your guess.

  • You picked B. Read on. At the end, the chapter comes back to your guess.

  • You picked C. Read on. At the end, the chapter comes back to your guess.

By the end you can

Ravi has a tap that fills 5 litres every minute. He plots minutes across and litres up. The rule is y = 5x.

Draw it first

Plot the tap

  1. A graph with the x axis time x (minutes) and the y axis water y (litres). Step 1 plots five dots: (1, 5), (2, 10), (3, 15), (4, 20) and (5, 25). Step 2 draws a straight line named y = 5x through them. Step 3 adds a dot at the start of the line, (0, 0).123456510152025300time x (minutes)water y (litres)

    1 Plot a dot for each minute: (1, 5), (2, 10), (3, 15), (4, 20), (5, 25).

  2. A graph with the x axis time x (minutes) and the y axis water y (litres). Step 1 plots five dots: (1, 5), (2, 10), (3, 15), (4, 20) and (5, 25). Step 2 draws a straight line named y = 5x through them. Step 3 adds a dot at the start of the line, (0, 0).y = 5x123456510152025300time x (minutes)water y (litres)

    2 The dots lie in a straight line. Draw the line through them.

  3. A graph with the x axis time x (minutes) and the y axis water y (litres). Step 1 plots five dots: (1, 5), (2, 10), (3, 15), (4, 20) and (5, 25). Step 2 draws a straight line named y = 5x through them. Step 3 adds a dot at the start of the line, (0, 0).y = 5x123456510152025300time x (minutes)water y (litres)

    3 At 0 minutes there is 0 litres, so the line starts at (0, 0), the origin.

The graph of y = kx is always a straight line through the origin, the point (0, 0). The number k says how steep the line is. It is the gradient: how much y goes up for each 1 across. Here k = 5, so y goes up 5 for each 1 across.

A graph with the x axis x and the y axis y. Three straight lines all start at the origin: y = 0.5x, y = x, y = 2x. The bigger the number in front of x, the steeper the line.y = 0.5xy = xy = 2x1234561234560xy
A bigger k gives a steeper line. All three lines pass through the origin.

Worked example

Sketch the graph of y = 3x for x from 0 to 4.

  1. Choose some values of x: 0, 1, 2, 3 and 4.
  2. Work out y = 3x for each: y = 0, 3, 6, 9 and 12. The last is y = 12.
  3. Plot the points (0, 0), (1, 3), (2, 6), (3, 9) and (4, 12).
  4. Join them with a straight line. It goes through the origin.

Answer: A straight line through (0, 0) and (4, 12)

A graph with the x axis x and the y axis y. Dots at (0, 0), (1, 3), (2, 6), (3, 9) and (4, 12) lie on a straight line named y = 3x.y = 3x1234246810120xy
The graph of y = 3x.

A straight line is not enough. Compare y = 2x with y = 2x + 3. The second line is straight, but it crosses the y axis at 3, not at 0. When x = 0 it gives y = 3. Doubling x does not double y, so it is not proportion.

A graph with the x axis x and the y axis y. A line named y = 2x starts at the origin. A parallel line named y = 2x + 3 starts higher, with a dot at (0, 3) where it crosses the y axis.y = 2xy = 2x + 312345636912150xy
Both lines are straight. Only the one through the origin is proportion.

Now inverse proportion. Take y = 12 ÷ x, for x above 0. When x is 1, 2, 3, 4, y is 12, 6, 4, 3. The points do not lie in a line. They lie on a curve that falls.

See it three ways

With things

Rectangles that hold 12 squares: 1 across and 12 up, 2 across and 6 up, 3 across and 4 up.

As a picture

A graph with the x axis x and the y axis y. Dots at (1, 12), (2, 6), (3, 4), (4, 3), (6, 2), (12, 1) lie on a falling curve named y = 12 ÷ x. The curve never touches either axis.y = 12 ÷ x24681012246810120xy

In symbols

x × y = 12, so y = 12 ÷ x.

The curve gets very high near the y axis, and very close to the x axis far along. It comes as near as you like to each axis but never touches either. A y of 0 would need 12 ÷ x = 0, and no x gives that.

Worked example

Sketch the graph of y = 12 ÷ x for x from 1 to 12.

  1. Choose values of x that divide 12: 1, 2, 3, 4, 6 and 12.
  2. When x = 2, y = 12 ÷ 2 = 6.
  3. When x = 4, y = 12 ÷ 4 = 3.
  4. When x = 6, y = 12 ÷ 6 = 2.
  5. Plot the points and join them with a smooth curve. It falls and never touches the axes.

Answer: A smooth curve through (2, 6), (4, 3) and (6, 2)

You can also tell the two kinds apart from a table. For direct proportion, y ÷ x is the same every time. For inverse proportion, x × y is the same every time.

A table with the head x, y, y ÷ x, x × y. Rows: 2, 3, 1.5, 6; 4, 6, 1.5, 24; 6, 9, 1.5, 54; 8, 12, 1.5, 96.xyy ÷ xx × y231.56461.524691.5548121.596
Test a table: divide, then multiply. One column stays the same.

Worked example

A table has x = 2, 4, 6, 8 and y = 3, 6, 9, 12. Is y proportional to x, inversely proportional, or neither?

  1. Divide y by x for the first pair: 3 ÷ 2 = 1.5.
  2. Divide for the others: 6 ÷ 4, 9 ÷ 6 and 12 ÷ 8 are all 1.5.
  3. Now multiply: 2 × 3 = 6, but 4 × 6 = 24. This is not fixed.
  4. y ÷ x is always 1.5, so y is proportional to x, with k = 1.5.

Answer: Directly proportional, with k = 1.5

Try it

Plot y = 2x on squared paper

You need: squared paper, a ruler, a pencil.

  1. Draw an x axis from 0 to 4 and a y axis from 0 to 8.
  2. Plot the points (0, 0), (1, 2), (2, 4), (3, 6) and (4, 8).
  3. Lay the ruler along the points and draw the line.

What you will see: The points lie on one straight line, and the line passes through the origin. Each step across goes up 2.

If you cannot try it, this is what happens.
A graph with the x axis x and the y axis y. Dots at (0, 0), (1, 2), (2, 4), (3, 6) and (4, 8) lie on a straight line named y = 2x.y = 2x123424680xy

A wrong idea many people have

Any straight line shows direct proportion.

Why it feels right: Direct proportion makes a straight line, so a straight line feels like proof.

The test that breaks it: Take y = 2x + 3. When x = 1, y = 5. When x = 2, which is double, y = 7. That is not double 5.

What is true: Direct proportion needs a straight line through the origin. Zero of x must give zero of y.

A wrong idea many people have

If y goes down as x goes up, the graph shows inverse proportion.

Why it feels right: Inverse proportion does go down as x goes up, so any fall looks like it.

The test that breaks it: Take y = 10 − x. It falls as x goes up. When x = 2, y = 8, and x × y = 16. When x = 4, y = 6, and x × y = 24. The product is not fixed.

What is true: Inverse proportion needs x × y to stay the same. Its graph is a curve that never touches the axes, not a straight line.

Key words

origin
the point (0, 0), where the two axes cross.
gradient
how steep a line is: how much y goes up for each 1 across.

Back to your guess

The answer is B: The graph is a straight line that goes through the origin.

Direct proportion makes a straight line through the origin, the point where both amounts are zero. A straight line that misses the origin is not proportion. A curve that falls and never touches the axes shows inverse proportion.

Check yourself

Try each one before you look. A wrong answer tells you where to go next.

  1. Which description fits the graph of y = kx, with k above 0?

    Tap your answer.
    1. Not this one. A straight line that misses the origin, such as y = 2x + 3, is not proportion. When x is 0, y must be 0. Go to M4.2.7. Try another.

    2. Not this one. That is the graph of y = k ÷ x, inverse proportion. The graph of y = kx rises in a straight line. Go to M4.2.7. Try another.

    3. Yes, that is right. When x = 0, y = k × 0 = 0, so the line passes through the origin. All the points are in a straight line because y goes up by k for each 1 across.

    4. Not this one. k is the steepness of the line, not where it crosses the y axis. The line y = kx crosses the y axis at 0. Go to M4.2.7. Try another.

    See the answer

    A straight line through the origin

    When x = 0, y = k × 0 = 0, so the line passes through the origin. All the points are in a straight line because y goes up by k for each 1 across.

    • If you chose A: A straight line that misses the origin, such as y = 2x + 3, is not proportion. When x is 0, y must be 0. Go to M4.2.7.
    • If you chose B: That is the graph of y = k ÷ x, inverse proportion. The graph of y = kx rises in a straight line. Go to M4.2.7.
    • If you chose D: k is the steepness of the line, not where it crosses the y axis. The line y = kx crosses the y axis at 0. Go to M4.2.7.
  2. The table shows x and y. Which is it?

    A table with the head x, y. Rows: 2, 8; 3, 12; 5, 20; 6, 24.xy28312520624
    Tap your answer.
    1. Yes, that is right. y ÷ x is 8 ÷ 2 = 4 for every pair, so y = 4x.

    2. Not this one. In inverse proportion y goes down when x goes up. Here y goes up with x, so it is not inverse. Go to M4.2.6. Try another.

    3. Not this one. Divide y by x for each pair: 8 ÷ 2, 12 ÷ 3, 20 ÷ 5 and 24 ÷ 6 are all 4. A fixed answer means direct proportion. Go to M4.2.6. Try another.

    See the answer

    Direct proportion, y = 4x

    y ÷ x is 8 ÷ 2 = 4 for every pair, so y = 4x.

    • If you chose B: In inverse proportion y goes down when x goes up. Here y goes up with x, so it is not inverse. Go to M4.2.6.
    • If you chose C: Divide y by x for each pair: 8 ÷ 2, 12 ÷ 3, 20 ÷ 5 and 24 ÷ 6 are all 4. A fixed answer means direct proportion. Go to M4.2.6.
  3. The table shows x and y. Which is it?

    A table with the head x, y. Rows: 1, 16; 2, 8; 4, 4; 8, 2.xy116284482
    Tap your answer.
    1. Not this one. In direct proportion y goes up when x goes up. Here y goes down as x goes up. Go to M4.2.6. Try another.

    2. Yes, that is right. x × y is 1 × 16 = 16 for every pair, so y = 16 ÷ x.

    3. Not this one. Multiply x by y for each pair: 1 × 16, 2 × 8, 4 × 4 and 8 × 2 are all 16. A fixed answer means inverse proportion. Go to M4.2.6. Try another.

    See the answer

    Inverse proportion, y = 16 ÷ x

    x × y is 1 × 16 = 16 for every pair, so y = 16 ÷ x.

    • If you chose A: In direct proportion y goes up when x goes up. Here y goes down as x goes up. Go to M4.2.6.
    • If you chose C: Multiply x by y for each pair: 1 × 16, 2 × 8, 4 × 4 and 8 × 2 are all 16. A fixed answer means inverse proportion. Go to M4.2.6.
  4. The table shows x and y. Which is it?

    A table with the head x, y. Rows: 1, 4; 2, 6; 3, 8; 4, 10.xy142638410
    Tap your answer.
    1. Not this one. Divide y by x: 4 ÷ 1 = 4, but 6 ÷ 2 = 3. The answer is not fixed. Also, when x = 0 this pattern would give y = 2, not 0. Go to M4.2.6. Try another.

    2. Not this one. In inverse proportion y goes down as x goes up. Here y goes up with x, and x × y is 4, 12, 24 and 40. Go to M4.2.6. Try another.

    3. Yes, that is right. Dividing y by x gives 4, 3, 2.67 and 2.5, which is not fixed. The product x × y is 4, 12, 24 and 40, which is not fixed either. The pattern is y = 2x + 2, a straight line that misses the origin.

    See the answer

    Neither

    Dividing y by x gives 4, 3, 2.67 and 2.5, which is not fixed. The product x × y is 4, 12, 24 and 40, which is not fixed either. The pattern is y = 2x + 2, a straight line that misses the origin.

    • If you chose A: Divide y by x: 4 ÷ 1 = 4, but 6 ÷ 2 = 3. The answer is not fixed. Also, when x = 0 this pattern would give y = 2, not 0. Go to M4.2.6.
    • If you chose B: In inverse proportion y goes down as x goes up. Here y goes up with x, and x × y is 4, 12, 24 and 40. Go to M4.2.6.
  5. y is proportional to x. The graph is a straight line through the origin and through the point A (4, 10). What is k?

    A graph with the x axis x and the y axis y. A straight line named y = kx starts at the origin. A dot named A (4, 10) is on the line, with dashed lines down to the x axis and across to the y axis.A (4, 10)y = kx12345636912150xy
    Tap your answer.
    1. Not this one. You divided x by y. The number k is y ÷ x, which is 10 ÷ 4. Go to M4.2.6. Try another.

    2. Not this one. You took 4 away from 10. Proportion divides: k = y ÷ x. Go to M4.2.6. Try another.

    3. Not this one. 10 is the y value of A. k is how much y goes up for each 1 across, which is 10 ÷ 4. Go to M4.2.6. Try another.

    4. Yes, that is right. k = y ÷ x = 10 ÷ 4 = 2.5. For every 1 across, the line goes up 2.5.

    See the answer

    2.5

    k = y ÷ x = 10 ÷ 4 = 2.5. For every 1 across, the line goes up 2.5.

    • If you chose A: You divided x by y. The number k is y ÷ x, which is 10 ÷ 4. Go to M4.2.6.
    • If you chose B: You took 4 away from 10. Proportion divides: k = y ÷ x. Go to M4.2.6.
    • If you chose C: 10 is the y value of A. k is how much y goes up for each 1 across, which is 10 ÷ 4. Go to M4.2.6.
  6. The curve shows inverse proportion. It passes through (2, 6), (3, 4) and (4, 3). Which formula is right?

    A graph with the x axis x and the y axis y. A falling curve passes through three dots: (2, 6), (3, 4), (4, 3).2468246810120xy
    Tap your answer.
    1. Yes, that is right. x × y is 2 × 6 = 12, 3 × 4 = 12, 4 × 3 = 12. The product is always 12, so y = 12 ÷ x.

    2. Not this one. This fits (2, 6), but when x = 3 it gives 9, not 4. It is also a rising line, not a falling curve. Go to M4.2.6. Try another.

    3. Not this one. This fits (2, 6), but when x = 3 it gives 5, not 4. A straight line is not inverse proportion. Check x × y for each point. Go to M4.2.6. Try another.

    See the answer

    y = 12 ÷ x

    x × y is 2 × 6 = 12, 3 × 4 = 12, 4 × 3 = 12. The product is always 12, so y = 12 ÷ x.

    • If you chose B: This fits (2, 6), but when x = 3 it gives 9, not 4. It is also a rising line, not a falling curve. Go to M4.2.6.
    • If you chose C: This fits (2, 6), but when x = 3 it gives 5, not 4. A straight line is not inverse proportion. Check x × y for each point. Go to M4.2.6.
  7. From an earlier chapter

    y is inversely proportional to x. When x = 5, y = 6. Find y when x = 3.

    See the answer

    10

    k = x × y = 5 × 6 = 30. Then y = 30 ÷ 3 = 10.

  8. y is proportional to x. The graph is a straight line through the origin and through the point (6, 21). What is k?

    See the answer

    3.5

    k = y ÷ x = 21 ÷ 6 = 3.5.

Keep it

Copy this into your exercise book.

The graph of y = kx is a straight line through the origin. The graph of y = k ÷ x is a curve that never touches the axes. A table: y ÷ x fixed is direct, x × y fixed is inverse.

Draw: A straight line through the origin beside a falling curve, with y ÷ x and x × y written under them.

Key words, A to Z

Every key word in this book, what it means, and the chapter that teaches it.

compound interest
interest worked out on the amount so far, including interest already added. M4.2.3
constant of proportionality
the fixed number k in y = kx or y = k ÷ x. M4.2.6
decay
a fall by the same percent every period. The multiplier is below 1. M4.2.4
directly proportional
y = kx for a fixed number k. Doubling x doubles y. M4.2.6
gradient
how steep a line is: how much y goes up for each 1 across. M4.2.7
growth
a rise by the same percent every period. The multiplier is above 1. M4.2.4
interest
extra amount added to savings each year, worked out as a percent. M4.2.3
inversely proportional
y = k ÷ x for a fixed number k. Doubling x halves y. M4.2.6
lowest common multiple
the smallest whole number above 0 that both numbers divide into. For 3 and 4 it is 12. M4.2.5
model
a rule that says how an amount changes, such as multiplying by 0.85 every year. M4.2.4
multiplier
the number you multiply by to change an amount, such as 1.12 for a rise of 12%. M4.2.1
origin
the point (0, 0), where the two axes cross. M4.2.7
original amount
the amount before the change. It is 100%. M4.2.2
percent
out of 100. So 12% is 12 out of 100, or 0.12. M4.2.1
percentage change
the change divided by the original amount, times 100. M4.2.1
simple interest
interest that is always a percent of the start amount, so it is the same every year. M4.2.3